How LongAccumulator and DoubleAccumulator classes work?
LongAccumulator
and DoubleAccumulator
. They are designed to accumulate (more on what does that mean later) values across threads safely while being extremely fast. A test is worth a thousand words, so here is how it works:class AccumulatorSpec extends Specification {So the accumulator takes a binary operator and combines initial value with every accumulated value. That means
public static final long A = 1
public static final long B = 2
public static final long C = 3
public static final long D = -4
public static final long INITIAL = 0L
def 'should add few numbers'() {
given:
LongAccumulator accumulator = new LongAccumulator({ long x, long y -> x + y }, INITIAL)
when:
accumulator.accumulate(A)
accumulator.accumulate(B)
accumulator.accumulate(C)
accumulator.accumulate(D)
then:
accumulator.get() == INITIAL + A + B + C + D
}
((((0 + 1) + 2) + 3) + -4)
equals to 2
. Don't go away yet, there's much more than that. Accumulator can take other operators as well, as illustrated by this use case:def 'should accumulate numbers using operator'() {Obviously accumulator would work just as well under heavy multi-threaded environment - which it was designed for. Now the question is, what other operations are permitted in
given:
LongAccumulator accumulator = new LongAccumulator(operator, initial)
when:
accumulator.accumulate(A)
accumulator.accumulate(B)
accumulator.accumulate(C)
accumulator.accumulate(D)
then:
accumulator.get() == expected
where:
operator | initial || expected
{x, y -> x + y} | 0 || A + B + C + D
{x, y -> x * y} | 1 || A * B * C * D
{x, y -> Math.max(x, y)} | Integer.MIN_VALUE || max(A, B, C, D)
{x, y -> Math.min(x, y)} | Integer.MAX_VALUE || min(A, B, C, D)
}
LongAccumulator
(this applies to DoubleAccumulator
as well) and why? JavaDoc is not very formal this time (bold mine):The order of accumulation within or across threads is not guaranteed and cannot be depended upon, so this class is only applicable to functions for which the order of accumulation does not matter. The supplied accumulator function should be side-effect-free, since it may be re-applied when attempted updates fail due to contention among threads. The function is applied with the current value as its first argument, and the given update as the second argument.In order to understand how
LongAccumulator
works, what type of operations are permitted and why it's so fast (because it is, compared to e.g AtomicLong
), let's start from the back, the get()
method:transient volatile long base;Which can be rewritten to not-exactly-equivalent but easier to read:
transient volatile Cell[] cells;
private final LongBinaryOperator function;
public long get() {
Cell[] as = cells; Cell a;
long result = base;
if (as != null) {
for (int i = 0; i < as.length; ++i) {
if ((a = as[i]) != null)
result = function.applyAsLong(result, a.value);
}
}
return result;
}
public long get() {Or even more functionally without internal state:
long result = base;
for (Cell cell : cells)
result = function.applyAsLong(result, cell.value);
return result;
}
public long get() {We clearly see that there is some internal
return Arrays.stream(cells)
.map(s -> s.value)
.reduce(base, function::applyAsLong);
}
cells
array and that in the end we must go through that array and apply our operator function sequentially on each element. Turns out LongAccumulator
has two mechanisms for accumulating values: a single base
counter and an array of values in case of high lock thread contention. If LongAccumulator
is used under no lock contention, only a single volatile base
variable and CAS operations are used, just like in AtomicLong
. However if CAS fails, this class falls back to an array of values. You don't want to see the implementation, it's 90 lines long, occasionally with 8 levels of nesting. What you need to know is that it uses simple algorithm to always assign given thread to the same cell (improves cache locality). From now on this thread has its own, almost private copy of counter. It shares this copy with couple of other threads, but not with all of them - they have their own cells. So what you end up in the end is an array of semi-calculated counters which must be aggregated. This is what you saw in get()
method.This brings us again to the question, what kind of operators (
op
) are permitted in LongAccumulator
. We know that the same sequence of accumulations under low load will result e.g. in:((I op A) op B) //get()Which means all values are aggregated in base variable and no counter array is used. However under high load,
LongAccumulator
will split work e.g. into two buckets (cells) and later accumulate buckets as well:(I op A) //cell 1or vice-versa:
(I op B) //cell 2
(I op A) op (I op B) //get()
(I op B) //cell 1Clearly all invocations of
(I op A) //cell 2
(I op B) op (I op A) //get()
get()
should yield the same result, but it all depends on the properties of op
operator being provided (+
, *
, max
, etc.)Commutative
We have no control over the order of cells and how they are assigned. That's why((I op A) op (I op B))
and ((I op B) op (I op A))
must return the same result. More compactly we are looking for such operators op
where X op Y = Y op X
for every X
and Y
. This means op
must be commutative.Neutral element (identity)
Cells are logically initialized with identity (initial) valueI
. We have no control over the number and order of cells, thus the identity value can be applied numerous times in any order. However this is an implementation detail, so it shouldn't affect the result. More precisely, for every X
and any op
:X op I = I op X = XWhich means the identity (initial) value
I
must be a neutral value for every argument X
to operator op
.Associativity
Assume we have the following cells:I op A // cell 1but the next time they were arranged differently
I op B // cell 2
I op C // cell 3
((I op A) op (I op B)) op (I op C) //get()
I op C // cell 1Knowing that
I op B // cell 2
I op A // cell 2
((I op C) op (I op B)) op (I op A) //get()
op
is commutative and I
is a neutral element, we can prove that (for every A
, B
and C
):((I op A) op (I op B)) op (I op C) = ((I op C) op (I op B)) op (I op A)Which proves that
(A op B) op C = (C op B) op A
(A op B) op C = A op (B op C)
op
must be associative in order for LongAccumulator
to actually work.Wrap up
LongAccumulator
and DoubleAccumulator
are highly specialized classes new in JDK 8. JavaDoc is quite vaque but we tried to prove properties that an operator and initial value must fullfil in order for them to do their job. We know that the operator must be associative, commutative and have a neutral element. It would have been so much better if JavaDoc clearly stated that it must be an abelian monoid ;-). Nevertheless for practical purposes these accumulators work only for adding, multiplying, min and max, as these are the only useful operators (with appropriate neutral element) that play well. Subtracting and dividing for example is not associative and commutative, thus can't possibly work. To make matters worse, accumulators would simply behave undeterministically.
Tags: concurrency, java 8, multithreading